/* Problem 9--Making Book
   This was a very easy problem.  The only thing you had to notice was
   that A might be greater than B; the problem never stated otherwise.*/

#include <stdio.h>
#include <stdlib.h>

int main (int argc, char **argv);

int main (int argc, char **argv) {

  FILE *in, *out;
  int ct[10], A, B, t, P, cs;

 in = fopen ("prob9.in","r");
 out = fopen ("prob9.out","w");
 for (cs=1;fscanf (in,"%d",&A),A > 0;cs++) {
  fscanf (in,"%d",&B);
  if (A > B) { /* Are A and B out of order? */
   t = A; A = B; B = t;
  }
  t = 0; /* Initialize array */
  for (t=0;t<10;t++) ct[t] = 0;
  for (t=A;t<=B;t++) /* We pull off the ones digit of each number */
   for (P=t;P>0;P/=10) /* and divide it by 10 */
    ct[P%10]++;
  fprintf (out,"Case %d: ",cs);
  for (t=0;t<10;t++)  /* Print answer */
   fprintf (out,"%d:%d ",t,ct[t]);
  fprintf (out,"\n");
 }
 fclose (in);
 fclose (out);
 return EXIT_SUCCESS;
}