/* Problem 5--Haiku
   This isn't too bad.  Just read the string and count the syllables as
   specified. */

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

FILE *in, *out;

int main (int argc, char **argv);

int main (int argc, char **argv) {
 char line[201];
 int L[3], l, v, i;

 in = fopen ("prob5.in","r");
 out = fopen ("prob5.out","w");
 while (fgets (line,sizeof line,in),line[strlen(line)-1]=0,
        strcmp (line,"e/o/i")!=0) {
  L[0] = L[1] = L[2] = 0;
  l = v = 0;
  for (i = 0; i < strlen (line); i++) { /* Is it a vowel? */
   if (line[i]=='a'||line[i]=='e'||line[i]=='i'||line[i]=='o'||
       line[i]=='u'||line[i]=='y') {
    if (!v) L[l]++; /* If previous letter was not a vowel, add one to */
    v=1;            /* the syllable count */
   } else if (line[i]!='/') v=0;
   else {    /* End of line; parse next one */
    l++;v=0;
   }
  }  /* Print out where the error is, if any */
  if (L[0] != 5) fprintf (out,"1\n");
  else if (L[1] != 7) fprintf (out,"2\n");
  else if (L[2] != 5) fprintf (out,"3\n");
  else fprintf (out,"Y\n");
 }
 fclose (in);
 fclose (out);
 return EXIT_SUCCESS;
}
